Civil Engineering Practice • Transportation Engineering
Stopping Sight Distance & Curve Length
6 min read
Worked: a 60 mph crest
On the level: 1.47 × 60 × 2.5 = 220.5 ft of reaction, plus 60²/(30 × 0.348) = 345.0 ft of braking, so SSD = 565.5 ft. A crest from +2.5% to −1.5% has A = 4, so L = 4 × 565.5²/2,158 = 593 ft. Check the assumption: S = 565.5 < L = 593. It holds.
Check it stuck: a set from Transportation Engineering, the knowledge area this unit teaches.
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